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Eight chairs are numbered 1 to 8. Two wo...

Eight chairs are numbered 1 to 8. Two women and three men wish to occupy one chair each. First the women choose the chairs from amongst the chairs marked 1 to 4, and then the men select the chairs from amongst the remaining. The number of possible arrangements is:

A

`""^(4)C_(3)xx""^(4)C_(2)`

B

`""^(4)C_(2)xx""^(4)P_(3)`

C

`""^(4)P_(2)xx""^(4)P_(3)`

D

`""^(4)P_(2)xx""^(6)P_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to follow the steps outlined below: ### Step 1: Women Choosing Chairs The two women can choose chairs from the first four chairs (1, 2, 3, 4). We need to select 2 chairs out of these 4 for the women. The number of ways to choose 2 chairs from 4 can be calculated using the combination formula: \[ \text{Number of ways} = \binom{n}{r} = \frac{n!}{r!(n-r)!} \] where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose. Here, \( n = 4 \) and \( r = 2 \): \[ \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \] ### Step 2: Arranging Women in the Chosen Chairs After choosing the chairs, the two women can occupy the selected chairs in different arrangements. The number of ways to arrange 2 women in 2 chosen chairs is given by: \[ 2! = 2 \times 1 = 2 \] ### Step 3: Men Choosing Chairs After the women have chosen their chairs, there will be 2 chairs occupied by women and 2 chairs left from the first four. This means there are 4 chairs remaining for the men to choose from (the 2 remaining from the first four and the 4 from chairs 5 to 8). Therefore, the men can choose from 6 available chairs. The number of ways to choose 3 chairs from these 6 is: \[ \binom{6}{3} = \frac{6!}{3!(6-3)!} = \frac{6 \times 5 \times 4}{3 \times 2 \times 1} = 20 \] ### Step 4: Arranging Men in the Chosen Chairs After the men have chosen their chairs, they can occupy the selected chairs in different arrangements. The number of ways to arrange 3 men in 3 chosen chairs is given by: \[ 3! = 3 \times 2 \times 1 = 6 \] ### Final Calculation Now, we can calculate the total number of arrangements by multiplying the results from all the steps: \[ \text{Total arrangements} = (\text{Ways to choose chairs for women}) \times (\text{Ways to arrange women}) \times (\text{Ways to choose chairs for men}) \times (\text{Ways to arrange men}) \] \[ = 6 \times 2 \times 20 \times 6 \] \[ = 6 \times 2 = 12 \] \[ 12 \times 20 = 240 \] \[ 240 \times 6 = 1440 \] Thus, the total number of possible arrangements is **1440**.
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