Home
Class 12
MATHS
ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that AB and CD are parallel and `BC bot CD`. If `angleADB = theta, BC = p and CD = q`, then AB is equal to

A

`(p^(2) + q^(2) cos theta)/(p cos theta + q sin theta)`

B

`(p^(2) + q^(2))/(p^(2) cos theta + q^(2) sin theta)`

C

`((p^(2)+q^(2))sin theta)/((p cos theta + q sin theta)^(2))`

D

`((p^(2)+q^(2))sin theta)/((p cos theta + q sin theta)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

ABCD is a trapezium such that AB and CD are parallel and BCbotCD . if angleADB=theta ,BC=p and CD=q, then AB is equal to

ABCD is a trapezium such that AB and CD are parallel and BC perp CD. If /ADB= theta BC=p and CD=q', then AB is equal to

ABCD is a trapezium such that AB and CD are parallel and BCbotCD if angleABD=theta,Bc=p and CD=q, then AB is equal to

ABCD is a trapezium such that AB and DC are parallel and BC is perpendicular to them. If BC=1 cm, CD=2 cm and angleADB=45^(@) , then the lengths of AB is (in cm)

ABCD is a trapezium such that AB, DC is parallel and BC is perpendicular to them. If angle (DAB) = 45^(@) , BC = 2 cm and CD = 3 cm, then find the length of AB?

ABCD is a trapezium such that AB|CD and CB is perpendicular to them.If /_ADB=theta,BC=p, and CD=q, show that AB=((p^(2)+q^(2))sin theta)/(p cos theta+q sin theta)

In Delta ABC, If AD _|_ BC, then AB^2 + CD^2 is equal to