Home
Class 12
MATHS
In a !ABC , medians AD and BE are drawn....

In a `!ABC` , medians AD and BE are drawn. If AD = 4, `angleDAB=pi//6` and `angleABE=pi//3` then the area of `!ABC` is

A

`(16)/(3sqrt(3))`

B

`(32)/(3sqrt(3))`

C

`(64)/(3sqrt(3))`

D

`8//3`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

In a Delta ABC, medians AD and BE are drawn.If AD=4,/_DAB=(pi)/(6) and /_ABE=(pi)/(3) then the area of Delta ABC is

In a triangle ABC, medians AD and CE are drawn.If AD=5,/_DAC=(pi)/(8) and /_ACE=(pi)/(4) then the area of the triangle ABC is equal to (5a)/(b), then a+b is equal to

In triangle ABC medians AD and CE are drawn,if AD=5,/_DAC=(pi)/(8) and /_ACE=(pi)/(4), then the area of triangle ABC is equal to a.(25)/(8) b.(25)/(3) c.(25)/(18) d.(10)/(3)

In triangle ABC, dedians AD and CE are drawn.If /_DAC=(pi)/(8), and /_ACE=(pi)/(4) then the area of the triangle ABC is equal to (25)/(9) (b) (25)/(3)(c)(25)/(18) (d) (10)/(3)

ABC is a triangle whose medians AD and BE are perpendicular to each other.If AD=p and BE=q then area of /_ABC is

ABC is a triangle whose medians AD and BC are perpendicular to each other.If AD=p and BE=q then area of /_ABC is

Two medians AD and BE of Delta ABC intersect at G at right angles If AD=9cm and BE=6cm then the length of BD in cm is

If in a !ABC,angleA=pi//3 and AD is a median , then

If in a triangleABC, A=pi/3 and AD is the median, then

In a triangle ABC if the equation of the medians AD and BE are 2x + 3y - 6=0 and 3x-2y-10=0 respectively and AD = 6, BE = 11, then find the area of the Triangle ABC : (A) 32 (B) 38 (C) 44 (D) 48