Section (A) : Position vector, Direction Ratios & Direction cosines: A-1. If the vector `vec b` is collinear with the vect,`vec a`=`(2 sqrt 2, -1,4) ` and `|vec b|`=6 then:

Section (A): Position vector,Direction Ratios & Direction cosines: A^(-1). If the vector vec b is collinear with the vect,vec a=(2sqrt(2),-1,4) and |vec b|=6 then:

If the vector vec b is collinear with the vector vec a(2sqrt(2),-1,4) and |vec b|=10, then

If the vector vec(b) is collinear to the vector bar(a) and bar(a)=(2sqrt(2),-1,4) and |vec(b)|=10 then ……………

Find the vector a which is collinear with the vector vec b=2hat i-hat j and vec a*vec b=10

The vec b which is collinear with the vector vec a=(2,1,-1) and satisfies the relation vec a*vec b=3 is

Three non-zero vectors vec(a), vec(b), vec(c) are such that no two of them are collinear. If the vector (vec(a)+vec(b)) is collinear with the vector vec(c) and the vector (vec(b)+vec(c)) is collinear with vector vec(a) , then prove that (vec(a)+vec(b)+vec(c)) is a null vector.

Let vec a, vec b and vec c be three non zero vectors such that no two of these are collinear. If the vector vec a + 2 vec b is collinear with vec c and vec b + 3 vec c is collinear with vec a then vec a + 2 vec b + 6 vec c =

If vec(A) = 3 hat(i) + 6 hat(j) - 2hat(k) , the directions of cosines of the vector vec(A) are

If the vectors vec a = 2i+3j+6k and vec b are collinear and |vec b| = 21 , then vec b =