Show that the planes 2x – 3y – 7z = 0, 3x – 14y – 13z = 0, 8x – 31y – 33z = 0 pass through the one line find its equations.

Prove that the lines 3x + 2y + z – 5 = 0 = x + y – 2z – 3 and 2x – y – z = 0 = 7x + 10y – 8z – 15 are perpendicular

(i) Find the equation of the plane passing through (1,-1,2) and perpendicular to the planes : 2 x + 3y - 2z = 5 , x + 2y - 3z = 8 . (ii) find the equation of the plane passing through the point (1,1,-1) and perpendicular to each of the planes : x + 2y + 3z - 7 = 0 and 2x - 3y + 4z = 0 . (iii) Find the equation of the plane passing through the point (-1,-1,2) and perpendicular to the planes : 3x + 2y - 3z = 1 and 5x - 4y + z = 5.

(i) Find the equation of the plane passing through the intersection of the planes : 2x - 7y + 4z = 3 and 3x - 5y + 4z + 11 = 0 and the point (-2, 1,3). (ii) Find the equation of plane through the intersection of planes : 3x - y + 2z - 4 = 0 and x + y + z - 2 = 0 and the point (2,2,1) .

If x =a, y=b, z=c is a solution of the system of linear equations x + 8y + 7z =0, 9 x + 2y + 3z =0, x + y+z=0 such that point (a,b,c ) lies on the plane x + 2y + z=6, then 2a+ b+c equals

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 =0 . If the plane is perpendicular to the plane 3x - y - 2z - 4 = 0 , then the value of p is equal to

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 = 0 If the plane is perpendicular to the plane , 3x - y - 2z - 4 = 0 then the value of p is equal to

Find the equation of a plane passing through the intersection of the planes x-3y+2z-5 - 0 and 2x+y+3z-1 = 0 and passes through the point (1,-2,3) .

Find the equation of plane passing through the intersection of plane 2x + 3y + 4z - 5 = 0 and 3x + 4y - 7z + 8 =0 and alos passing through (1, 1, 1).