The equation of the line passing through `(1, 1, 1)` and perpendicular to the line of intersection of the planes `x+2y-4z=0 and 2x-y+2z=0` is

Equation of the line passing through (1,1,1) and perpendicular to the plane 2x+3y-z-5=0 is

Equation of a line passing through (-1,2,-3) and perpendicular to the plane 2x+3y+z+5=0 is

Equation of the line passing through (1,1,1) and parallel to the plane 2x+3y+z+5=0

Lying in the plane x+y+z=6 is a line L passing through (1, 2, 3) and perpendicular to the line of intersection of planes x+y+z=6 and 2x-y+z=4 , then the equation of L is

Find the equation of the line passing through the point (4,-14,4) and intersecting the line of intersection of the planes : planes :3x+2y-z=5 and x-2y-27=-1 at right angles.

Find an equation or the line that passes through the point P(2,\ 3,\ 1) and is parallel to the line of intersection o the planes x+2y-3z=4\ a n d\ x-2y+z=0 .

(i) Find the equation of the plane passing through (1,-1,2) and perpendicular to the planes : 2 x + 3y - 2z = 5 , x + 2y - 3z = 8 . (ii) find the equation of the plane passing through the point (1,1,-1) and perpendicular to each of the planes : x + 2y + 3z - 7 = 0 and 2x - 3y + 4z = 0 . (iii) Find the equation of the plane passing through the point (-1,-1,2) and perpendicular to the planes : 3x + 2y - 3z = 1 and 5x - 4y + z = 5.

Equation of the plane passing through the point (1,1,1) and perpendicular to each of the planes x+2y+3z=7 and 2x-3y+4z=0 l is

Find an equation for the plane through P_(0)=(1, 0, 1) and passing through the line of intersection of the planes x +y - 2z = 1 and x + 3y - z = 4 .