y=a e^(-1/x)+b is a solution of (dy)/...

`y=a e^(-1/x)+b` is a solution of `(dy)/(dx)=y/(x^2),` then (a) `( b ) (c) a in R (d)` (e) (b) 0 (c) `( d ) (e) b=1( f )` (g) (d) `( h ) a (i)` (j) takes finite number of values

`a in R`

b=0

b=1

a takes finite number of values

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A, B

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