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(ln(secx+tanx)/(cosx)dx=(ln(secy+tany)/(...

`(ln(secx+tanx)/(cosx)dx=(ln(secy+tany)/(cosy)dy`

Text Solution

Verified by Experts

The correct Answer is:
`ln^2(secx +tanx) - ln^2(sec y + tan y) =C`
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