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If the line l x+m y+n=0 cuts the elli...

If the line `l x+m y+n=0` cuts the ellipse `((x^2)/(a^2))+((y^2)/(b^2))=1` at points whose eccentric angles differ by `pi/2,` then find the value of `(a^2l^2+b^2m^2)/(n^2)` .

A

`x^2l^2 +b^2n^2 = 2m^2`

B

`a^2m^2 + b^2l = 2n^2`

C

`a^2l^2 + b^2m^2 =2n^2`

D

`a^2n^2 + b^2m^2 = 2l`

Text Solution

Verified by Experts

The correct Answer is:
C
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