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x-2y+4=0 is a common tangent to y^2=4x a...

`x-2y+4=0` is a common tangent to `y^2=4x and x^4/4+y^2/b^2=1.` Then the value of b and the other common tangent are given by : (A) `b=sqrt3` (B) `x+2y+4=0` (C) `b=3` (D) `x-2y-4=0`

A

`b = sqrt3, x +2y +4 =0`

B

`b =3, x+2y +4 =0`

C

`b =sqrt3, x+ 2y + 4 =0`

D

`b = sqrt3, x -2y -4 =0`

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The correct Answer is:
A
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