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lf the eccentricity of the hyperbola `x^2-y^2(sec)alpha=5` is `sqrt3` times the eccentricity of the ellipse `x^2(sec)^2alpha+y^2=25,` then a value of `alpha` is : (a) `pi/6` (b) `pi/4` (c) `pi/3` (d) `pi/2`

A

`(pi//6)`

B

`pi//4`

C

`pi//3`

D

`pi//4`

Text Solution

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The correct Answer is:
B
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