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If theta is the angle between the asympt...

If `theta` is the angle between the asymptotes of the hyperbola `(x^2)/(a^2)-(y^2)/(b^2)=1` with eccentricity `e`, then `sec (theta/2)` can be

A

e

B

`e//2`

C

`e//3`

D

`1//e`

Text Solution

Verified by Experts

The correct Answer is:
A
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