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Examine which is greater : sin x tan x o...

Examine which is greater : sin x tan x or `x^(2)`, Hence evaluate `underset(hto0)("lim") [(sin x tanx)/(x^(2))], " Where " x in (0,(pi)/(2))`

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The correct Answer is:
`{:(" "lim),(x rarr 0):} [(sin x tan x)/(x^(2))]=1`
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