Home
Class 12
MATHS
To illustrate the Mean Value Theorem wit...

To illustrate the Mean Value Theorem with a specific function, let’s consider`f(x) = x^(3) – x, a= 0, b = 2`. since f is a polynomial, it is continuous and differentiable for x, so it is certainly continuous on [0, 2] and differentiable on (0, 2) such that `f(2) – f(0) = f'(c)(2 – 0)`

Text Solution

Verified by Experts

The correct Answer is:
But c must lie in (0, 2) , so `c=2//sqrt(3)`.
The tangent line at this value of c is parallel to the secant line OB.
Promotional Banner

Topper's Solved these Questions

  • MONOTONOCITY

    MOTION|Exercise Exercise - 1 ( Objective Problems ) (SECTION-A ) ( FINDING INTERVALS OF MONOTONOCITY)|7 Videos
  • MONOTONOCITY

    MOTION|Exercise Exercise - 1 ( Objective Problems ) ( SECTION -B ) (FINDING VALUE OF VARIABLE GIVEN MONOTONIC BEHAVIOUR )|2 Videos
  • METHOD OF DIFFERENTIATION

    MOTION|Exercise EXERCISE - 4 LEVEL -II|5 Videos
  • PARABOLA

    MOTION|Exercise EXERCISE - IV|33 Videos

Similar Questions

Explore conceptually related problems

Let f be any continuous function on [0, 2] and twice differentiable on (0, 2). If f(0) = 0, f(1) = 1 and f(2) = 2, then :

If f(x)={ax^(2)+b,x 1;b!=0, then f(x) is continuous and differentiable at x=1 if

The function f(x)={{-x^(2)+6, if 0<=x<2 },{ x-1, if 2<=x<=4 }, then find if f(x) is continuous, differentiable or both.

If f(x) is continuous in [0,2] and f(0)=f(2). Then the equation f(x)=f(x+1) has

Let f(x)={(x^(p)"sin"1/x,x!=0),(0,x=0):} then f(x) is continuous but not differentiable at x=0 if

If f is continuously differentiable function then int_(0)^(2.5) [x^2] f'(x) dx is equal to