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In the sum of first n terms of an A.P. i...

In the sum of first n terms of an A.P. is `cn^2`, then the sum of squares of these n terms is

A

`(n(4n^2 -1)c^2)/(6)`

B

`(n(4n^2+1)c^2)/(3)`

C

`(n(4n^2-1)c^2)/(3)`

D

`(n(4n^2+1)c^2)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
C
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