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ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that `AB and CD` are parallel and `BC _|_ CD`. If /_ADB= theta , BC =p and CD=q`, then AB is equal to

A

`(p^2 +q^2)/(p^2 cos q+ q^2 sin q)`

B

`((p^2 +q^2)sin theta)/((p cos theta+ q sin theta)^2)`

C

`((p^2 +q^2)sin theta)/(p cos theta + q sin theta)`

D

`(p^2 +q^2 cos theta)/(p cos theta+ q sin theta)`

Text Solution

Verified by Experts

The correct Answer is:
C
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