If ` 2^x=4^y=8^zand(1/(2x)+1/(4y)+1/(6z))=24/7,t h e n z=? a. 7/48 \ \ \ \ \ \ b. 48/7 \ \ \ \ \ c . 44/7`

If 2^(x)=4^(y)=8^(z) and ((1)/(2x)+(1)/(4y)+(1)/(6z))=(24)/(7) , then find the value of z.

2x + 3y-5z = 7, x + y + z = 6,3x-4y + 2z = 1, then x =

Solve x + y = 7 , y + z = 4 , z + x = 1

If 3x-4y+z=7; 2x-z+3y=19 ; x+2y+2z=24 , then what is the value of z ? (a) 4 (b) 5 (c) 6 (d) 8

The value of k such that (x-4)/1=(y-2)/1=(z-k)/2 lies in the plane 2x-4y+z=7 is a. 7 b. -7 c. no real value d. 4

The value of k such that (x-4)/1=(y-2)/1=(z-k)/2 lies in the plane 2x-4y+z=7 is a. 7 b. -7 c. no real value d. 4

Find the angle between the planes : (i) 3 x - 6y - 2z = 7 " " 2x + y - 2z = 5 (ii) 4 x + 8y + z = 8 " " and y + z = 4 (iii) 2 x - y + z =6 " " and x + y + 2z = 7 .

Given that 10^0.48=x , 10^(0.70)=y and x^z=y^2, then the value of z is close to a. 1. 45 b. 1. 88 c. 3. 7 d. 2. 9