If `log_e((a+b)/2)=1/2(log_e a+log_e b),` then find the relation between `a a n d b dot`

If log_e(1/(2)(a+b))=1/2(log_e a+log_e b), then a/(3b) =

If log_(b) n = 2 and log_(n) 2b = 2 , then find the value of b.

If log_(b)n=2 and log_(n)(2b)=2 , then nb=

The value of (6a^((log)_e b)((log)_(a^2)b)((log)_(b^2)a)/(e^((log)_e a(log)_e b))i s independent of a (b) independent of b dependent on a (d) dependent on b

If x=log_(k)b=log_(b)c=(1)/(2)log_(c)d, then log_(k)d is equal to

Solve : log_e (x-a) + log_e x =1 (a>0)

Let b_i > 1 for i =1, 2,....,101. Suppose log_e b_1, log_e b_2,....,log_e b_101 are in Arithmetic Progression (A.P.) with the common difference log_e 2. Suppose a_1, a_2,...,a_101 are in A.P. such that a_1 = b_1 and a_51 = b_51. If t = b_1 + b_2+.....+b_51 and s = a_1+a_2+....+a_51 then

"If "log_(e)(log_(e) x-log_(e)y)=e^(x^(2_(y)))(1-log_(e)x)," then find the value of "y'(e).