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The number of N=6-(6(log)(10)2+(log)(10)...

The number of `N=6-(6(log)_(10)2+(log)_(10)31)` lies between two successive integers whose sum is equal to (a)5 (b) 7 (c) 9 (c) 10

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`N in(I_1,I_2)`
`N=6-[6log_10^2+log_10^31]`
`N=6-[log_10^(2^6)+log_10^31]`
`N=6-[log_10^32+log_10^31]`
`N=6-[log_10^(32*31)]`
`N=6-log_10^992`
`N=6-log_10^(10^3-8)]`
`N=6-(3^-)`
...
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