Home
Class 12
PHYSICS
The time of flight of a projectile is 10...

The time of flight of a projectile is 10 s and range is 500m. Maximum height attained by it is [`g=10 m//s^(2)`]

A

25 m

B

50 m

C

82 m

D

125 m

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • PROJECTILE MOTION

    MOTION|Exercise EXERCISE-2|22 Videos

  • PROJECTILE MOTION

    MOTION|Exercise EXERCISE-3 (SECTION-A)|11 Videos

  • PROJECTILE MOTION

    MOTION|Exercise EXERCISE-3 (SECTION-B)|8 Videos

  • PHOTOELECTRIC EFFECT

    MOTION|Exercise EXERCISE -3 (PREVIOUS YEAR PROBLEMS (JEE MAIN))|12 Videos

  • RADIOACTIVITY & NUCLEAR PHYSICS

    MOTION|Exercise Exercise-3|81 Videos

Similar Questions

Explore conceptually related problems

A stone is projected in air. Its time of flight is 3s and range is 150m. Maximum height reached by the stone is (Take, g = 10 ms^(-2))

Range of a projectile with time of flight 10 s and maximum height 100 m is : (g= -10 m//s ^2)

The maximum horizontal range of a projectile is 400 m . The maximum value of height attained by it will be

A projectile is thrown with speed u making angle theta with horizontal at t =0 . It just crosses two points of equal height at time t = 1 s and t = 3 s respectively. Calculate the maximum height attained by it ? (g = 10 m//s^(2) )

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s. Then the maximum height attained by it : - (g=10 m//s^2)

A projectile is thrown with speed u making angle theta with horizontal at t=0 . It just crosses the two points at equal height at time t=1 s and t=3 sec respectively. Calculate maximum height attained by it. (g=10 m//s^(2))

A stone is projected vertically upwards.When it reaches half the maximum height,its velocity is 20m/s.What is the maximum height attained by the stone? (g=10m/s^(2)

If the horizontal range of a projectile be a and the maximum height attained by it is b, then prove that the velocity of projection is

Assertion : If time of flight in a projectile motion is made two times, its maximum height will become four times. Reason : In projectile motion H prop T^2 , where H is maximum height and T the time of flight.

A projectile is fired to have maximum range 500 m. Maximum height attained by the projectitle in this case will be

MOTION-PROJECTILE MOTION-EXERCISE-1
  1. The kinetic energy of a projectile at the highest point is-

    Text Solution

    |

  2. For angles of projection of a projectile at angle (45^(@) - theta) and...

    Text Solution

    |

  3. The time of flight of a projectile is 10 s and range is 500m. Maximum ...

    Text Solution

    |

  4. Two seconds after projection, a projectile is travelling in a directio...

    Text Solution

    |

  5. A particle is projected with a speed V from a point O making an angle ...

    Text Solution

    |

  6. Two projectiles are thrown simultaneously in the same plane from the s...

    Text Solution

    |

  7. Two projectivles are thrown simultaneously in the same plane from the ...

    Text Solution

    |

  8. A ball is hit by a batsman at an angle of 37^(@) as shown in figure. T...

    Text Solution

    |

  9. A projectile is fired with a speed u at an angle theta with the horizo...

    Text Solution

    |

  10. A person is standing on a truck moving with a constant velocity of 14....

    Text Solution

    |

  11. Two particles are projected from the same point with the same speed at...

    Text Solution

    |

  12. A man on a moving cart, facing the direction of motion, thrown a ball ...

    Text Solution

    |

  13. A particle is projected with velocity u at an angle alpha from a point...

    Text Solution

    |

  14. One second after the projection, a stone moves at an angle of 45^@ wi...

    Text Solution

    |

  15. In previous questions, the initial velocity of projection of stone is-

    Text Solution

    |

  16. The equation of a projectile is y=sqrt(3)x-(gx^(2))/(2) the angle of...

    Text Solution

    |

  17. The equation of projectile is y = 16 x - (5 x^2)/(4). Find the horizon...

    Text Solution

    |

  18. The trajectory of a projectile fired horizontally with velocity u is p...

    Text Solution

    |

  19. A cannon on a level plane is aimed at an angle theta above the horizon...

    Text Solution

    |

  20. A projectile is thorwn with a velocity of 50ms^(-1) at an angle of 53^...

    Text Solution

    |