A particle is moving along a straight line from point A to point B. The position vectors for points A and B are `(2hati+7hatj-3hatk)and(5hati-3hatj-6hatk)`m respectively. One of the force acting on the particle is `vecF=20hati-30hati+15hatk` N. Find the work done by this force.

Explanation

To find the work done by the force on the particle moving from point A to point B, we can follow these steps:

### Step 1: Determine the position vectors of points A and B
The position vectors are given as:
- Point A: \(\vec{A} = 2\hat{i} + 7\hat{j} - 3\hat{k}\) m
- Point B: \(\vec{B} = 5\hat{i} - 3\hat{j} - 6\hat{k}\) m

### Step 2: Calculate the displacement vector \(\vec{AB}\)
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