A force `vecF=xhati+y^(2)hatjN` acts on a particle and the particle moves from `(1,2) m` to `(–3,4) m`. Find work done by the force `vecF`.

Explanation

To find the work done by the force \(\vec{F} = x \hat{i} + y^2 \hat{j} \, \text{N}\) as the particle moves from the point \((1, 2) \, \text{m}\) to \((-3, 4) \, \text{m}\), we can follow these steps:

### Step 1: Understand the Work Done Formula
The work done \(W\) by a force along a path can be expressed as:
\[ W = \int \vec{F} \cdot d\vec{s} \]
where \(d\vec{s}\) is the differential displacement vector.
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