A force of `(3hati-1.5hatj)N` acts on `5kg` body. The body is at a position of `(2hati-3hatj)m` and is travelling at `4m//s`. The force acts on the body until it is at the position `(hati+5hatj)m`. Calculate final.speed.

Explanation

Given, Mass of the body = 5 kg
Force `vecF=3hati-1.5hatj`
Displacement `vec(Deltas)={(hati+5hatj)-(2hati-3hatj)}m=(-hati+8hatj)m`
From Work Energy theorem
`W=vecF.Deltavecs=(1)/(2)m(v^(2)-u^(2))`
`-3-12=(1)/(2)xx5[v^(2)-(4)^(2)]`
`impliesv=sqrt(10)m//s`