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A 1-KW motor pumps out water from a well...

A `1-KW` motor pumps out water from a well `10m` deep. Calculate the quantity of water pumped out per second.

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Power, `P = 1` kilowatt = `10^(3)` watt
`S = 10 m` , Time, `t = 1` second , Mass of water, m = ?
Power = `(mgxxs)/(t)`
`therefore 10^(3)=(mxx9.8xx10)/(1)`
or `m=(10^(3))/(9.8xx10)kg=10.204kg`
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