Home
Class 12
PHYSICS
A small body is placed at rest at the bo...

A small body is placed at rest at the bottom B of a smooth hemispherical surface of wedge as shown. If the wedge is shifted horizontally towards right with acceleration `a_(0) = 3g`, find speed of the body w.r.t the wedge at the instant the body reaches points A.

Text Solution

Verified by Experts

Here we need calculation w.r.t the wedge which is accelerated i.e. non-inertial frame of reference, So we have to consider Pseudo force `(F_(P))` and work done by the Pseudo force `(W_(P))` also.
Where `F_(P) = ma_(0) = 3mg` and is towards left i.e. apposite to `a_(0)`
By work-energy theorem for motion from B to A
`F_(P)R-mgR=(1)/(2)m(v^(2)-0)`

`implies3mgR-mgR=(1)/(2)mv^(2)`
`therefore v=2sqrt(gR)`
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER & ENERGY

    MOTION|Exercise QUESTIONS FOR PRACTICE|25 Videos

  • WORK, POWER & ENERGY

    MOTION|Exercise Exercise - 1|42 Videos

  • WORK, POWER & ENERGY

    MOTION|Exercise EXAMPLES|24 Videos

  • WAVES

    MOTION|Exercise EXERCISE -4 (Level -II) (previous year JEE Advanced)|10 Videos

Similar Questions

Explore conceptually related problems

A small ball is placed at the top of a smooth hemispherical wedge of radius R. If the wedge is accelerated with an acceleration a, find the velocity of the ball relative to wedge as a function of theta .

A small body of mass 'm' is placed at the top of a smooth sphere of radius 'R' placed on a horizontal surface as shown, Now the sphere is given a constant horizontal acceleration a_(0) = g . The velocity of the body relative to the sphere at the moment when it loses contact with the sphere is

Rod A can slide in vertical direction pushing the triangular wedge B towards right. The wedge is moving toward right with uniform acceleration a_(s). Find acceleration of the rod A.

A small block of mass m is placed at rest on the top of a smooth wedge of mass M, which in turn is placed at rest on a smooth horizontal surface as shown in figure. It h be the height of wedge and theta is the inclination, then the distacne moved by the wedge as the block reaches the foot of the wedge is

Figure shows a block A constrained to slide along the inclined plane of the wedge B shown. Block A is attached with a string which passes through three ideal pulleys and connected to the wedge B. If wedge is pulled toward right with an acceleration a, find (a) the acceleration of the block with respect to wedge (b) the acceleration of the block with respect to ground.

A block of mass m = 10 kg is released from the top of the smooth inclined surface of a wedge which is moving horizontally toward right at a constant velocity of u = 10 m/s. Inclination of the wedge is theta=37^(@) . Calculate the work done by the force applied by the wedge on the block in two seconds in a reference frame attached to - (a) the ground (b) the wedge. [Take g=10 m//s^(2) ]

A block of mass m is placed at the bottom of a massless smooth wedge which if placed on a horizontal surface. When we push the wedge with a constant force, the block moves up the wedge. Find the work done by the external agent when the block has a speed v and is reaches the top of the wedge.

A block of mass 2kg slides down the face of a smooth 45^@ wedge of mass 9 kg as shown in the figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge.