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Under the action of a force, a 2 kg body...

Under the action of a force, a `2 kg` body moves such that its position x as a function of time is given by `x =(t^(3))/(3)` where x is in metre and t in second. The work done by the force in the first two seconds is .

A

1600 joules

B

160 joules

C

16 joules

D

1.6 joules

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The correct Answer is:
C
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MOTION-WORK, POWER & ENERGY -Exercise - 1
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