A charged particle of mass `5 mg` and charge `q=+2muC` has velocity `vecv=2hati-3hatj+4hatk`. Find out the magnetic force on the charged particle and its acceleration at this instant due to magnetic field `vecB=3hatj-2hatk, vecv` and `vecB` are in `m//s` and `Wb//m^(2)` respectively.

Explanation

`vecF=qvecvxxvecB=2xx10^(-6)(2hati-3hatjxx4hatk)xx(3hatj-2hatk)`
`=2xx10^(-6)[-6hati+4hatj+6hatk]N`
By Newton 's Law `veca=(vecF)/(m)`
`=(2xx10^(-6))/(5xx10^(-6))(-6hati+4hatj+6hatk)`
`=0.8(-3hati+2hatj+3hatk)m//s^(2)`