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A charged particle has acceleration veca...

A charged particle has acceleration `veca=2hati=xhatj` in a magnetic field `vecB=-3hati+2hatj-4hatk`.Find the value of `x`.

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`becausevecFbotvecB`
`thereforevecabotvecB`
`thereforeveca.vecB=0`
`therefore(2hati+xhatj).(-3hati+2hatj-4hatk)=0`
`rArr-6+2x=0 rArrx=3`.
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MOTION-MAGNETISM -1-Exercise - 3 SECTION -A
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