Home
Class 12
PHYSICS
A particle of mass 0.5 gm and charge 2.5...

A particle of mass 0.5 gm and charge `2.5xx10^(-8)` coulomb is moving with velocity `6xx10^(4)m//s`, horizontally what should be the value of magnetic field acting on it so that the particle is able to move in a straight line - `(g=9.8m//s^(2))`

A

`0.327" Weber"//m^(2)`

B

`3.27" Weber"//m^(2)`

C

`32.7"Weber"//m^(2)`

D

this is not possible

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • MAGNETISM -1

    MOTION|Exercise Exercise - 1 SECTION -C,D :- Magnetic force on charge and current carrying wire|27 Videos
  • MAGNETISM -1

    MOTION|Exercise Exercise - 1 SECTION -E :- torque on a current carrying loop and magnetic dipole moment|13 Videos
  • MAGNETISM -1

    MOTION|Exercise Exercise - 1 SECTION -A :- Magnetif field due to straight wire|10 Videos
  • MAGNETISM

    MOTION|Exercise EXERCISE-4 (LEVEL-II)|40 Videos
  • MATTER WAVE

    MOTION|Exercise EXERCISE 3 (SECTION B)|7 Videos

Similar Questions

Explore conceptually related problems

A particle of mass 0.6g and having charge of 25 n_(C) is moving horizontally with a uniform velocity 1.2xx10^(4)ms^(-1) in a uniform magnetic field, then the value of the magnetic induction is (g=10ms^(-2))

An alpha particle is moving with a velocity of (7 xx 10^(5) hat i m//s) in a magnetic field of (5 hat i + 9 hat j ) . T . Find the magnetic force acting on the particle.

A wire is moving with velocity 12xx10^(-2) m/s in a magnetic field of 0.5 T. if the induced emf is 9 mV, the length of wire is

An alpha - particle is moving field of (4hati - hatj) tesla with a velocity of (6 xx 10^(5) hati) ms^(-1) . What will be the magnetic force acting on the particle?

An electron has mass 9xx10^(-31)kg and change 1.6xx10^(-19)C is moving with a velocity of 10^(6)m//s , enters a region where magnetic field exists. If it describes a circle of radius 0.10m , the intensity of magnetic field must be

A proton moving with a velocity of 2.5 xx 10^(7) m/s , enter a magnetic feildof 2T, making an angle of 30◦ with the magnetic field. The force acting on the proton

An alpha particle is moving with a velocity of (7 xx 10^(5) hat I m//s) in a magnetic field of (5 hat I + 9 hat j) T. Find the magnetic force acting on the particle.

A particle with 10^(-11) coulomb of charge and 10^(-7)kg mass is moving wilth a velocity of 10^(8)m//s along the y -axis. A uniform static magnetic field B=0.5 Tesla is acting along the x -direction. The force on the particle is

If particle of charge 10^(-12) coulomb moving along the hatx - direction with a velocity 10^(5)m//s experiences a force of 10^(-10) newton in haty - direction due to magnetic field, then the minimum magnetic field is

A proton moving withh a velocity 2.5xx10^(7)m//s enters a magnetic field of intensity 2.5T making an angle 30^(@) with the magnetic field. The force on the proton is