When a proton is released from rest in a room, it starts with an initial acceleration `a_(0)` towards west. When it is projected towards north with a speed `v_(0)` it moves with an initial acceleration `3a_(0)` towards west. The electric and magnetic fields in the room are:

Options

A. `(ma_(0))/(e)" east ",(3ma_(0))/(ev_(0))` down
B. `(ma_(0))/(e) " west ",(2ma_(0))/(ev_(0))`up
C. `(ma_(0))/(e) " west ",(2ma_(0))/(ev_(0))` down
D. `(ma_(0))/(e) "east" , (3ma_(0))/(ev_(0))`up

Answer

C