When [Ni(NH(3))(4)]^(2+) is treated with...

When `[Ni(NH_(3))_(4)]^(2+)` is treated with conc `HCI`, two compounds having the formula `Ni(NH_(3))(2)CI_(2)` are formed. A solution of I reacts with oxalic acid to form `Ni(NH_(3))_(2)(C_(2)O_(4))`. II does not react with oxalic acid. Deduce the configuration of I and II and the geometry of Ni (II) complexes .

I cis, II trans, both tetrahedral

I cis, II trans, both square planar

I trans, II cis, both tetrahedral

I trans, II cis, both sqaure planar

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When [Ni(NH_(3))_(4)]^(2+) is treated with conc HCI two compounds having the formula Ni(NH_(3))CI_(2) (designated as I and II are formed) I can be converted into II ny boiling in dil HCI A solution of I reacts with oxalic acid to form Ni(NH_(3))_(2)(C_(2)O_(4)) II does not react with oxalic acid Deduce the configuration Of I and II and the geometry of Ni (II) complexes .

On treatment of [Pt(NH_(3))_(4)]^(2+) with concentrated HCI, two compounds (P) and (Q) having the same formula, [Pt(NH_(3))_(2)CL_(2)] are obtained, (P) can be converted into (Q) by boiling with dilute HCI. A soution of (P) reacts with oxalic acid to form [Pt(NH_(3))_(2)(C_(2)O_(4))] whereas (Q) does not react. Point out the correct statement of the following :

The hexaaqua complex [Ni(H_(2)O)_(6)]^(2+) is green, whereas the corresponding ammonia complex [Ni(NH_(3))_(6)]^(2+) is violet. Explain.

The geometries of Ni(CO)_(4) and Ni(PPh_(3))_(2)CI_(2) are .

What is the IUPAC name of complex [Ni(NH_3)_6]Cl_2 ?

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