The set of quantum number for the `19^(th)` electrons in chromium is -

Options

A. `n =4, =0, m=0 s=+1//2 or -1//2`
B. `n =3, =2 ,m =1 , s= + 1//2 or -1//2`
C. `n =3, =2 m =-1, s = + 1//2 or -1//2`
D. `n =4, =1, m =0 s, = + 1//2 or -1//2`

Answer

A