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In an excited state of hydrogen like ato...

In an excited state of hydrogen like atom an electron has total energy of `-3.4 eV`. If the kinetic energy of the electron is E and its de-Broglie wavelength is `lambda`, then

A

`E=6.8 eV, lamda = 6.6 xx 10 ^(-10)m`

B

` E = 3.4 eV, lamda=6.6 xx 10 ^(-10)m`

C

`E=3.4 eV, lamda = 6.6 xx 10 ^(-11) m`

D

`E = 6.8 eV, lamda = 6.6 xx 10 ^(-11) m`

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The correct Answer is:
B
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