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The kinetic energy of an electron in the...

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_0` is Bohr radius] :

A

`(h ^(2))/(4pi^(2)ma _(0)^(2))`

B

`(h^(2))/(16pi^(2) ma _(1) ^(2))`

C

`(h^(2))/(32 pi^(2) ma _(0)^(2))`

D

`(h ^(2))/(64 pi ^(2) ma_(0)^(2))`

Text Solution

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The correct Answer is:
C
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