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A radioacive element decays by parallel ...

A radioacive element decays by parallel path as given below:
`A overset(lambda_(1))(to) lambda_(1) = 1.8 xx 10^(-2) sec^(-1)`
`2A overset(lambda_(2))(to) B lambda_(2) = 10^(-3) sec^(-1)`
Average life of radio nuclide A will be:

A

`52.63` sec

B

500 sec

C

50 sec

D

None

Text Solution

Verified by Experts

The correct Answer is:
C
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