Home
Class 12
CHEMISTRY
In Carius method of estimation of haloge...

In Carius method of estimation of halogens `250 mg` of an organic compound gave `141 mg` of `AgBr`. The percentage of bromine in the compound is (atomic mass `Ag = 108, Br = 80`)

A

48

B

60

C

24

D

36

Text Solution

Verified by Experts

The correct Answer is:
c

moles of Br `=1 times` moles of AgBr
`" "=1 times (141 times 10^(-3))/188`
moles of Br `=(141 times 10^(-3))/188 times 80` `therefore %` of Br `=(141 times 10^(-3))/188 times 80/(250 times 10^(-3)) times 100`
`" "=24%`
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT

    MOTION|Exercise EXERCISE - 1|64 Videos
  • MOLE CONCEPT

    MOTION|Exercise EXERCISE - 2 (LEVEL - I)|50 Videos
  • METALLURGY

    MOTION|Exercise EXERCISE 4 (LEVEL - II)|17 Videos
  • NOMENCLATURE OF ORGANIC COMPOUNDS

    MOTION|Exercise PREVIOUS YEAR|8 Videos

Similar Questions

Explore conceptually related problems

In Carcuc method for the estimation of halogens. 250 mg of organic compound gave 141 mg of AgBr . The percentage of bromine in the compound is :

In the Carius method of estimation of halogen. 0.25 g of an organic compound gave 0.188 g of AgBr. The percentage of bromine in the compound is (Molar mass of AgBr = 188 g mol^-1 )

0.4 g of Organic Compound gave 0.188 g of AgBr. The percentage of Br in the compound is