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Calculate the % of free SO(3) in oleum (...

Calculate the `%` of free `SO_(3)` in oleum ( a solution of `SO_(3)` in `H_(2)SO_(4)`) that is labelled `109% H_(2)SO_(4)` by weight.

Text Solution

Verified by Experts

109% `H_(2)SO_(4)`' refers to the total mass of pure `H_(2)SO_(4)`, i.e., 109 g that will be formed when 100 g of oleum is diluted by 9 g of `H_(2)O` which `(H_(2)O)` combines with all the free `SO_(3)` present in oleum to form `H_(2)SO_(4)`
`" "H_(2)O+SO_(3) rarr H_(2)SO_(4)`
1 mole of `H_(2)O` combines with mole of `SO_(3)`
or 18 g of `H_(2)O` combines with 80 g of `SO_(3)`
or 9 g of `H_(2)O` combines with 40 g of `SO_(3)`
Thus, 100 g of oleum contains 40 g of `SO_(3)` or oleum contains 40% of free `SO_(3)`.
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Oleum or fuming sulphuric acid contains SO_(3) dissolved in sulphuric acid and has the molecular formula H_(2)S_(2)O_(7) , It is formed by passing SO_(3) in H_(2)SO_(4) . When water is added to oleum, SO_(3) reacts with water to form H_(2)SO_(4) . SO_(3)(g) + H_(2)O(l) to H_(2)SO_(4)(aq) As a result, mass of H_(2)SO_(4) increases. When 100 g sample of oleum is diluted with desired amount of water (in gram) then the total mass of pure H_(2)SO_(4) obtained after dilution is known as percentage labelling of oleum. % Labelling of oleum = Total mass of H_(2)SO_(4) present in oleum after dilution or = Mass of H_(2)SO_(4) initially present + Mass of H_(2)SO_(4) produced after dilution From this, the percentage composition of H_(2)SO_(4) and SO_(3) (free) and SO_(3) (combined) can be calculated. The percentage of SO_(3) in 109% H_(2)SO_(4) is

Oleum or fuming sulphuric acid contains SO_(3) dissolved in sulphuric acid and has the molecular formula H_(2)S_(2)O_(7) , It is formed by passing SO_(3) in H_(2)SO_(4) . When water is added to oleum, SO_(3) reacts with water to form H_(2)SO_(4) . SO_(3)(g) + H_(2)O(l) to H_(2)SO_(4)(aq) As a result, mass of H_(2)SO_(4) increases. When 100 g sample of oleum is diluted with desired amount of water (in gram) then the total mass of pure H_(2)SO_(4) obtained after dilution is known as percentage labelling of oleum. % Labelling of oleum = Total mass of H_(2)SO_(4) present in oleum after dilution or = Mass of H_(2)SO_(4) initially present + Mass of H_(2)SO_(4) produced after dilution From this, the percentage composition of H_(2)SO_(4) and SO_(3) (free) and SO_(3) (combined) can be calculated. The percentage of free SO_(3) and H_(2)SO_(4) in 112% H_(2)SO_(4) is