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Calculate the number of Cl^(-) and Ca^(2...

Calculate the number of `Cl^(-)` and `Ca^(2+)` ions in `222 g` anhydrous `CaCl_(2)`.

A

2N ions of `Ca^(+2)4N` ions of `Cl^(-)`

B

2N ions of `Cl^(-)` & 4N ions of `Ca^(+2)`

C

1N ions of `Ca^(+2)` & 1N ions of `Cl^(-)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
a
mol. wt. of `CaCl_(2)=111g`
111 g `CaCl_(2)` has = N ions of `Ca^(+2)`
`therefore` 222g of `CaCl_(2) " has " (N times 222)/111`
= 2N ions of `Ca^(+2)`
Also 111 g `CaCl_(2)` has `=2N` ions of `Cl^(-)`
`therefore 222 g" "CaCl_(2)" has "=(2N times 222)/111` ions of `Cl^(-)`
= 4N ions of `Cl^(-)`.
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