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A silver coin weighing 11.34 g was disso...

A silver coin weighing 11.34 g was dissolved in nitric acid When sodium chloride was added to the solution all the silver (present as `AgNO_(3)`) precipitated as silver chloride. The mass of the precipitated silver chloride was 14.35 g. Calculate the percentage of silver in the coin.

A

`4.8%`

B

`95.2%`

C

`90%`

D

`80%`

Text Solution

Verified by Experts

The correct Answer is:
b
`Ag+2HNO_(3) rarr AgNO_(3)+NO_(2)+H_(2)O`
108
`AgNO_(3)+NaCl rarr NaNO_(3)`
`" "143.5`
`therefore` 143.5 gm of silver chloride would be precipitated by 108 g of silver.
or 14.35 g of silver chloride would be precipitated by 10.8 g of silver.
11.34 g of silver coin contain 10.8 g of pure silver.
`therefore` 100 g of silver coin contain `10.8/11.34 times 100=95.2%`.
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