Calculate the total ions & charge present in 4.2 gm of `N^(-3)`

Explanation

mole `="wt in gm"/"Ionic wt"=4.2/14=0.3`
total no of ions `=0.3 times N_(A)` ions
total charge `=0.3 N_(A) times 3 times 1.6 times 10^(-19)`
`=0.3 times 6.023 times 10^(23) times 3 times 1.6 times 10^(-19)`,
`=8.67 times 10^(4)C`