367.5 gm `KClO_(3)` (M = 122.5) when heated, How many litre of oxygen gas is proudced at S.T.P.

Explanation

`KClO_(3) rarr KCl +O_(2)`
Applying POAC on O, moles of O in `KClO_(3)`
= moles of O in `O_(2)`
`3 times " moles of "KClO_(3)=2 times " moles of "O_(2)`
`3 times 367.5/122.5=2 times n, n=3/2 times 367.5/122.5`
Volume of `O_(2)` gas at S.T.P = moles `times 22.4`
`=3/2 times 367.5/122.5 times 22.4=9 times 11.2=100.8` lit