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Out of 1.0 g dioxygen, 1.0 g (atomic) ox...

Out of 1.0 g dioxygen, 1.0 g (atomic) oxygen and 1.0 g of ozone, the maximum number of oxygen atoms are contained in -

A

1.0 g of atomic oxygen.

B

1.0 g of ozone.

C

1.0 g of oxygen gas.

D

All contain same number of atoms

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The correct Answer is:
To determine which of the three forms of oxygen (dioxygen, atomic oxygen, and ozone) contains the maximum number of oxygen atoms in 1.0 g, we will calculate the number of oxygen atoms in each case using the concept of moles. ### Step-by-step Solution: 1. **Identify the Molecular Weights**: - **Dioxygen (O₂)**: The molecular weight of dioxygen is \( 16 \, \text{g/mol} \times 2 = 32 \, \text{g/mol} \). - **Atomic Oxygen (O)**: The atomic weight of atomic oxygen is \( 16 \, \text{g/mol} \). - **Ozone (O₃)**: The molecular weight of ozone is \( 16 \, \text{g/mol} \times 3 = 48 \, \text{g/mol} \). 2. **Calculate Moles of Each Form**: - **Dioxygen (O₂)**: \[ \text{Moles of O₂} = \frac{1.0 \, \text{g}}{32 \, \text{g/mol}} = 0.03125 \, \text{mol} \] - **Atomic Oxygen (O)**: \[ \text{Moles of O} = \frac{1.0 \, \text{g}}{16 \, \text{g/mol}} = 0.0625 \, \text{mol} \] - **Ozone (O₃)**: \[ \text{Moles of O₃} = \frac{1.0 \, \text{g}}{48 \, \text{g/mol}} = 0.02083 \, \text{mol} \] 3. **Calculate the Number of Oxygen Atoms**: - **Dioxygen (O₂)**: Each molecule of O₂ contains 2 oxygen atoms. \[ \text{Number of O atoms in O₂} = 0.03125 \, \text{mol} \times 2 \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 3.77 \times 10^{22} \, \text{atoms} \] - **Atomic Oxygen (O)**: Each atom of O is a single oxygen atom. \[ \text{Number of O atoms in O} = 0.0625 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 3.76 \times 10^{22} \, \text{atoms} \] - **Ozone (O₃)**: Each molecule of O₃ contains 3 oxygen atoms. \[ \text{Number of O atoms in O₃} = 0.02083 \, \text{mol} \times 3 \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 3.76 \times 10^{22} \, \text{atoms} \] 4. **Compare the Number of Oxygen Atoms**: - Dioxygen: \( \approx 3.77 \times 10^{22} \, \text{atoms} \) - Atomic Oxygen: \( \approx 3.76 \times 10^{22} \, \text{atoms} \) - Ozone: \( \approx 3.76 \times 10^{22} \, \text{atoms} \) ### Conclusion: The maximum number of oxygen atoms is contained in **1.0 g of dioxygen (O₂)**.
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