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The per cent of N "in" 66% pure (NH(4))(...

The per cent of `N "in" 66%` pure `(NH_(4))_(2)SO_(4)` sample is:

A

32

B

28

C

14

D

None of these

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The correct Answer is:
C
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(NH_(4))_(2)SO_(4)+NaOH to

0.80g of impure (NH_(4))_(2) SO_(4) was boiled with 100mL of a 0.2N NaOH solution was neutralized using 5mL of a 0.2N H_(2)SO_(4) solution. The percentage purity of the (NH_(4))_(2)SO_(4) sample is:

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