Which has maximum number of atoms of oxygen

Options

A. 10 ml `H_(2)O(l)`
B. 0.1 mole of `V_(2)O_(5)`
C. 12 gm `O_(3)(g)`
D. `12.044 times 10^(22)` molecule of `CO_(2)`

Answer

To solve the problem of determining which option has the maximum number of oxygen atoms, we will analyze each option step by step.

### Given Options:
1. **10 ml of S2O (liquid)**
2. **0.1 moles of B2O5**
3. **12 grams of O3 (gas)**
4. **12.044 × 10^22 molecules of CO2**

### Step 1: Calculate the number of oxygen atoms in **10 ml of S2O**.

1. **Convert volume to moles**:
- The molar volume of a gas at STP is 22.4 L or 22,400 ml.
- Moles of S2O = Volume (ml) / Molar Volume (ml) = 10 ml / 22,400 ml = 0.000446 moles.

2. **Determine moles of oxygen**:
- S2O has 1 oxygen atom per molecule.
- Therefore, moles of oxygen = moles of S2O = 0.000446 moles.

3. **Convert moles of oxygen to atoms**:
- Number of atoms = moles × Avogadro's number = 0.000446 moles × 6.022 × 10^23 atoms/mole ≈ 2.686 × 10^20 atoms.

### Step 2: Calculate the number of oxygen atoms in **0.1 moles of B2O5**.

1. **Determine moles of oxygen**:
- B2O5 has 5 oxygen atoms per molecule.
- Therefore, moles of oxygen = 5 × moles of B2O5 = 5 × 0.1 = 0.5 moles.

2. **Convert moles of oxygen to atoms**:
- Number of atoms = 0.5 moles × 6.022 × 10^23 atoms/mole ≈ 3.011 × 10^23 atoms.

### Step 3: Calculate the number of oxygen atoms in **12 grams of O3**.

1. **Calculate moles of O3**:
- Molar mass of O3 = 3 × 16 g/mol = 48 g/mol.
- Moles of O3 = mass (g) / molar mass (g/mol) = 12 g / 48 g/mol = 0.25 moles.

2. **Determine moles of oxygen**:
- O3 has 3 oxygen atoms per molecule.
- Therefore, moles of oxygen = 3 × moles of O3 = 3 × 0.25 = 0.75 moles.

3. **Convert moles of oxygen to atoms**:
- Number of atoms = 0.75 moles × 6.022 × 10^23 atoms/mole ≈ 4.517 × 10^23 atoms.

### Step 4: Calculate the number of oxygen atoms in **12.044 × 10^22 molecules of CO2**.

1. **Calculate moles of CO2**:
- Moles of CO2 = 12.044 × 10^22 molecules / 6.022 × 10^23 molecules/mole ≈ 0.1999 moles.

2. **Determine moles of oxygen**:
- CO2 has 2 oxygen atoms per molecule.
- Therefore, moles of oxygen = 2 × moles of CO2 = 2 × 0.1999 ≈ 0.3998 moles.

3. **Convert moles of oxygen to atoms**:
- Number of atoms = 0.3998 moles × 6.022 × 10^23 atoms/mole ≈ 2.4079 × 10^23 atoms.

### Summary of Results:
- **S2O**: ≈ 2.686 × 10^20 atoms
- **B2O5**: ≈ 3.011 × 10^23 atoms
- **O3**: ≈ 4.517 × 10^23 atoms
- **CO2**: ≈ 2.4079 × 10^23 atoms

### Conclusion:
The maximum number of oxygen atoms is found in **12 grams of O3**, which has approximately **4.517 × 10^23 atoms**.

### Final Answer:
**The option with the maximum number of oxygen atoms is 12 grams of O3.**

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