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An iodized salt contains 0.5% of Nal. A ...

An iodized salt contains 0.5% of Nal. A person consumes 3 gm of salt everyday. The number of iodide ions going into his body everyday is

A

`10^(-4)`

B

`6.02 times 10^(-4)`

C

`6.02 times 10^(19)`

D

`6.02 times 10^(23)`

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The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the amount of NaI in the salt consumed Given that the iodized salt contains 0.5% NaI and a person consumes 3 grams of salt daily, we can find the amount of NaI in the consumed salt. \[ \text{Amount of NaI} = \left( \frac{\text{Percentage of NaI}}{100} \right) \times \text{Amount of salt consumed} \] \[ \text{Amount of NaI} = \left( \frac{0.5}{100} \right) \times 3 \, \text{g} = 0.015 \, \text{g} \] ### Step 2: Calculate the number of moles of NaI Next, we need to calculate the number of moles of NaI. The molecular weight of NaI can be calculated as follows: - Atomic weight of Na (Sodium) = 23 g/mol - Atomic weight of I (Iodine) = 126.9044 g/mol - Molecular weight of NaI = 23 + 126.9044 = 149.9044 g/mol (approximately 150 g/mol) Now, we can calculate the number of moles of NaI: \[ \text{Number of moles of NaI} = \frac{\text{Mass of NaI}}{\text{Molecular weight of NaI}} = \frac{0.015 \, \text{g}}{150 \, \text{g/mol}} = 0.0001 \, \text{mol} \] ### Step 3: Calculate the number of molecules of NaI Using Avogadro's number (approximately \(6.022 \times 10^{23}\) molecules/mol), we can find the number of molecules of NaI: \[ \text{Number of molecules of NaI} = \text{Number of moles} \times \text{Avogadro's number} \] \[ \text{Number of molecules of NaI} = 0.0001 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \approx 6.022 \times 10^{19} \, \text{molecules} \] ### Step 4: Calculate the number of iodide ions Since each molecule of NaI produces one iodide ion (I^-), the number of iodide ions will be equal to the number of molecules of NaI: \[ \text{Number of iodide ions} = \text{Number of molecules of NaI} \approx 6.022 \times 10^{19} \, \text{iodide ions} \] ### Final Answer The number of iodide ions going into the person's body every day is approximately \(6.022 \times 10^{19}\). ---
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