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For the reaction 2x+3y+4z rarr 5w In...

For the reaction
`2x+3y+4z rarr 5w`
Initially if 1 mole of x, 3 mole of y and 4 mole of z is taken. If 1.25 mole of w is obtained then % yield of this reaction is

A

`50%`

B

`60%`

C

`70%`

D

`40%`

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the percentage yield of the reaction \(2x + 3y + 4z \rightarrow 5w\), we will follow these steps: ### Step 1: Identify the Limiting Reagent From the initial amounts given: - Moles of \(x = 1\) - Moles of \(y = 3\) - Moles of \(z = 4\) The stoichiometric coefficients from the balanced equation indicate that: - 2 moles of \(x\) are required for every 5 moles of \(w\). - Thus, for 1 mole of \(x\), the theoretical yield of \(w\) can be calculated. ### Step 2: Calculate Theoretical Yield of \(w\) Using the stoichiometry of the reaction: - From the balanced equation, \(2 \text{ moles of } x\) produce \(5 \text{ moles of } w\). - Therefore, \(1 \text{ mole of } x\) will produce: \[ \text{Theoretical yield of } w = \left(\frac{5 \text{ moles of } w}{2 \text{ moles of } x}\right) \times 1 \text{ mole of } x = 2.5 \text{ moles of } w \] ### Step 3: Determine Actual Yield of \(w\) According to the problem, the actual yield of \(w\) obtained is \(1.25\) moles. ### Step 4: Calculate Percentage Yield The percentage yield can be calculated using the formula: \[ \text{Percentage Yield} = \left(\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\right) \times 100 \] Substituting the values: \[ \text{Percentage Yield} = \left(\frac{1.25}{2.5}\right) \times 100 = 50\% \] ### Final Answer The percentage yield of the reaction is **50%**. ---
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