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How many molecules of N(2) are contained...

How many molecules of `N_(2)` are contained in 1.12 litre of air if the volume content of `N_(2)` in air is 80% at N.T.P.

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The correct Answer is:
`2.4 times 10^(22)` molecules
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According to the Avogadro's law , equal number of moles of gases occupy the same volume at identical conditions of temperature and pressure. Even if we have a mixture of non-reacting gases then Avogadro's law is still obeyed by assuming mixture as a new gas. Now let us assume air to consist of 80% by volume of nitrogen (N_(2)) and 20% by volume of oxygen (O_(2)) . If air is taken at STP , then its 1 mol would occupy 22.4 L . 1 mol of air would contain 0.8 mol of N_(2) and 0.2 mol of O_(2) hence the mole fraction of N_(2) and O_(2) are given by X_(n_(2))=0.8, X_(o_(2))=0.2 Volume occupied by air at STP containing exactly 11.2 gm f nitrogen:

According to the Avogadro's law , equal number of moles of gases occupy the same volume at identical conditions of temperature and pressure. Even if we have a mixture of non-reacting gases then Avogadro's law is still obeyed by assuming mixture as a new gas. Now let us assume air to consist of 80% by volume of nitrogen (N_(2)) and 20% by volume of oxygen (O_(2)) . If air is taken at STP , then its 1 mol would occupy 22.4 L . 1 mol of air would contain 0.8 mol of N_(2) and 0.2 mol of O_(2) hence the mole fraction of N_(2) and O_(2) are given by X_(n_(2))=0.8, X_(o_(2))=0.2 If air is treated as a solution of O_(2) and N_(2) , then % w/w of oxygen is:

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