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NaBr, used to produce AgBr for use in ph...

NaBr, used to produce AgBr for use in photography can itself be prepared as follows :
`Fe+Br_(2) rarr FeBr_(2)`
`FeBr_(2)+Br_(2) rarr Fe_(3)Br_(8)`
`" "`(not (balanced)
`Fe_(3)Br_(8)+Na_(2)CO_(3) rarr NaBr+CO_(2)+Fe_(3)O_(4)`
`" "` (not balanced)
How much Fe, in kg, is consumed to produce `2.50 times 10^(3)` kg NaBr ?

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The correct Answer is:
509.7 kg
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Comprehension # 3 NaBr , used to produce AgBr for use in photography can be self prepared as follows : {:(,Fe+Br_(2)rarrFeBr_(2)," "..........(i),),(,FeBr_(2)+Br_(2)rarrFe_(3)Br_(8)," " ..........(ii) ," "("not balanced")),(,Fe_(3)Br_(8)+Na_(2)CO_(3)rarrNaBr+CO_(2)+Fe_(3)O_(4) , " ".......(iii)," "("not balanced")):} How much Fe in kg is consumed to produce 2.06xx10^(3) kg Nabr " "........(iv) If yield of (iii) reaction is 90% then mole of CO_(2) formed when 2.06xx10^(3) kg NaBr is formed.

Comprehension # 3 NaBr , used to produce AgBr for use in photography can be self prepared as follows : {:(,Fe+Br_(2)rarrFeBr_(2)," "..........(i),),(,FeBr_(2)+Br_(2)rarrFe_(3)Br_(8)," " ..........(ii) ," "("not balanced")),(,Fe_(3)Br_(8)+Na_(2)CO_(3)rarrNaBr+CO_(2)+Fe_(3)O_(4) , " ".......(iii)," "("not balanced")):} How much Fe in kg is consumed to produce 2.06xx10^(3) kg Nabr " "........(iv) Mass of iron required to produce 2.06xx10^(3) kg NaBr

Comprehension # 3 NaBr , used to produce AgBr for use in photography can be self prepared as follows : {:(,Fe+Br_(2)rarrFeBr_(2)," "..........(i),),(,FeBr_(2)+Br_(2)rarrFe_(3)Br_(8)," " ..........(ii) ," "("not balanced")),(,Fe_(3)Br_(8)+Na_(2)CO_(3)rarrNaBr+CO_(2)+Fe_(3)O_(4) , " ".......(iii)," "("not balanced")):} If the yield of (ii) is 60% & (iii) reaction is 70% then mass of ion required to produce 2.06xx10^(3) kg NaBr .

FeCr_(2)O_(4)+Na_(2)CO_(3)+O_(2) to Fe_(2)O_(3)darr+Na_(2)CrO_(4)

In the reaction Br_(2) +Na_(2) CO_(3) rarr NaBr + NaBrO_(3) + CO_(2) The equiv. wt. of NaBrO_(3) is

Na_(2)CO_(3)+Fe_(2)O_(3)rarr A+CO_(2) , what is A in the reaction ?

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