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The dissociation constant of weak acid H...

The dissociation constant of weak acid `HA` is `4.9xx10^(-8)`. After making the necessary approximations, calculate `pH` in `0.1 M` acid.

A

1.155

B

2.155

C

3.155

D

4.155

Text Solution

Verified by Experts

The correct Answer is:
D
For weak acid `K_a=alpha^(2).C`
`therefore alpha=sqrt((K_a)/(C))=sqrt((4.9 xx 10^(-8))/(0.1))`
`=7 xx 10^(-4)`
`pH =-log H^(+)=-log alpha C`
`=-log 7 xx 10^(-4) xx 10^(-1)`
=4.1549 =4.155
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