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Calculate the pH of solution obtained by...

Calculate the `pH` of solution obtained by mixing `10 ml` of `0.1 M HCl` and `40 ml` of `0.2 M H_(2)SO_(4)`

A

0.3685

B

0.4685

C

1.3685

D

1.4684

Text Solution

Verified by Experts

The correct Answer is:
B
Milli equivalent of `H^+` from HCl `=10 xx 0.1= 1`
Milli equivalent of `H^+" from "H_2SO_4 =40 xx 0.2 xx 2=16`
Total Meq of `H^+` in solution =1+16=17
`H^(+)=(17)/(50)=3.4 xx 10^(-1) [? [H^+]=("Meq")/("V in ml")]`
`pH=-log[H^(+)]=-log[0.34] =0.4685`
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